u-can-do
In the case of a pentagonal 'addition' Arithmagon diagram, the puzzle can be solve simply by adding the 5 box numbers and then divide by 2. Again, that gives you a "center" number for the pentagon. Then for each corner circle or vertice value, take the sum of the two boxes (not opposite or adjacent to it) and subtract it from the ‘center’ number.
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© G R Burgin 2009